In the design of electronic devices, rotary encoder switches—such as digital potentiometers—are commonly used. Their English name is "Rotary Encoder Switch." Before writing the driver for this component, I did some research online using Google and Baidu to understand its functionality. I learned that it has three main functions: left rotation, right rotation, and pressing. It has five pins, and its physical appearance is shown below:
Here are the basic wiring connections: (1) Pins 1 and 3 should be connected with pull-up resistors, typically 10kΩ is sufficient; (2) Pin 2 is usually grounded; (3) Pins 4 and 5 are for the lower button switch (when pressed, pin 4 goes low). The actual wiring diagram I used during debugging is as follows:
In reality, it's not too complicated to use. However, many online resources mention that it's challenging to determine the direction of rotation. I want to clarify that this is just a misconception after reading my code. With my implementation, the issue becomes clear and straightforward!
The key to determining the direction of rotation lies in observing the edge of signal BMB when BMA is low. A rising edge indicates clockwise rotation, while a falling edge indicates counter-clockwise rotation. As long as the code is well-documented, the device should operate smoothly without issues.
Without further delay, here is the code:
#include <reg52.h>
#define uchar unsigned char
#define uint unsigned int
sbit BMA = P1^4;
sbit BMB = P1^5;
sbit BMC = P1^6;
sbit P27 = P2^7;
sbit P26 = P2^6;
sbit P25 = P2^5;
uchar code table[] = {0xC0, 0xF9, 0xA4, 0xB0, 0x99, 0x92, 0x82, 0xF8, 0x80, 0x90};
uchar count = 0;
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